I have a question about the following Ito's Lemma problem:
X(t) has the following process, dX(t) = 0.4dt+0.2dZ(t) where {Z(t)} is a standard Brownian Motion.
Let Y(t) = e^(w[X(t)+0.02t])
Y(t) satisfies the following stochastic differential equation: d ln Y(t) = a(w)dt + B(w)dZ(t).
Determine a(1/2).
(just to state the obvious, a is alpha, B is beta, w is omega)
I did this problem without using Ito's Lemmma, but got the same answer. I am hoping someone can tell me if my method will always work or if I just got lucky. I will give it a shot at explaining what I did:
Will this always work or did it just work out nicely for this problem?
Thanks for any input!
X(t) has the following process, dX(t) = 0.4dt+0.2dZ(t) where {Z(t)} is a standard Brownian Motion.
Let Y(t) = e^(w[X(t)+0.02t])
Y(t) satisfies the following stochastic differential equation: d ln Y(t) = a(w)dt + B(w)dZ(t).
Determine a(1/2).
(just to state the obvious, a is alpha, B is beta, w is omega)
I did this problem without using Ito's Lemmma, but got the same answer. I am hoping someone can tell me if my method will always work or if I just got lucky. I will give it a shot at explaining what I did:
1. Took log of Y(t). [ln Y(t) = w(X(t)+0.02t)]
2. differentiated both sides of Y(t) with respect to t. [d ln Y(t) = w(dX(t)+0.02dt)]
3. Substituted 0.4dt +0.2dZ(t) into dY(t) for the d(x(t) term. [d ln Y(t) = w(0.42dt+0.2dZ(t))]
4. Substituted w(0.42dt+0.2dZ(t)) into the d ln Y(t) term of d ln Y(t) = a(w)dt + B(w)dZ(t).
[ w(0.42dt+0.2dZ(t)) = a(w)dt + B(w)dZ(t)] ---> [ 0.42wdt+0.2wdZ(t)) = a(w)dt + B(w)dZ(t)]
5. Evaluated new equation for w=1/2. [ 0.21dt+0.1dZ(t)) = a(1/2)dt + B(1/2)dZ(t)]
6. "Observed" that a(1/2)=0.21 and B(1/2)=0.1
Will this always work or did it just work out nicely for this problem?
Thanks for any input!
Ito's Lemma Question
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