The probability of a computer chip to be defective is 0.05. Consider a package
of 6 computer chips.
(a) What is the probability one chip will be defective?
(b) What is the probability at least one chip will be defective?
(c) What is the probability that more than one chip will be defective, given
at least one is defective?
The only part I am not getting is part c. I can get most of it, but I am doing Beye's formula with P(A given B)=(P(B given A)P(A))/(P(B given A)P(A)) + (P(* given *)P(*).
I am using * as a placeholder, as this is my difficulty. Am I to do P(B given A compliment)? Or P(A given B compliment)? Or am I wrong on that in either case?
of 6 computer chips.
(a) What is the probability one chip will be defective?
(b) What is the probability at least one chip will be defective?
(c) What is the probability that more than one chip will be defective, given
at least one is defective?
The only part I am not getting is part c. I can get most of it, but I am doing Beye's formula with P(A given B)=(P(B given A)P(A))/(P(B given A)P(A)) + (P(* given *)P(*).
I am using * as a placeholder, as this is my difficulty. Am I to do P(B given A compliment)? Or P(A given B compliment)? Or am I wrong on that in either case?
Bernoulli binomial with conditional Prob.
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