For two lives with lifetime variables S and T, you are given that
f(s,t)= (s+t)/125 for 0<s<5 and 0<t<5.
Calculate the probability that the last survivor status (2:2) survives on year.
Can someone tell why my solution is wrong. Here is my solution:
Probability that the last survivor status (2:2) survives on year=p2+p2-p2:2 = 59/63
p2=S(3)/S(2) =13/18 where is S(x)=Integral(x to 5) of f(s)ds=(50-x^2-5x)/50 with
f(s) is the marginal of s= Integral(0 to 5) of f(s,t)dt=(2s+5)/50
p2:2 = 32/63 previously calculated.
Thanks
f(s,t)= (s+t)/125 for 0<s<5 and 0<t<5.
Calculate the probability that the last survivor status (2:2) survives on year.
Can someone tell why my solution is wrong. Here is my solution:
Probability that the last survivor status (2:2) survives on year=p2+p2-p2:2 = 59/63
p2=S(3)/S(2) =13/18 where is S(x)=Integral(x to 5) of f(s)ds=(50-x^2-5x)/50 with
f(s) is the marginal of s= Integral(0 to 5) of f(s,t)dt=(2s+5)/50
p2:2 = 32/63 previously calculated.
Thanks
ASM 13 ed, Example 54E: Multiples Live, Last Survivor Probabilities
