Can anybody assist me with a question i'm having problems with?
In the asm,
p2= (1.2 C 2) * (1/1+20)^0.2 * (20/1+20)^2
= 0.12 * 0.543946 * 0.907029
= 0.0592
my question is how did they come up with the 0.12? basically, i do not know how to solve (1.2 choose 2)...any help?? i cannot seem to find a formula in the asm manual. Thanks
In the asm,
p2= (1.2 C 2) * (1/1+20)^0.2 * (20/1+20)^2
= 0.12 * 0.543946 * 0.907029
= 0.0592
my question is how did they come up with the 0.12? basically, i do not know how to solve (1.2 choose 2)...any help?? i cannot seem to find a formula in the asm manual. Thanks
Question under Negative Binomial
