Affichage des articles dont le libellé est How to solve for growth rate in geometric annuities. Afficher tous les articles
Affichage des articles dont le libellé est How to solve for growth rate in geometric annuities. Afficher tous les articles

How to solve for growth rate in geometric annuities

mardi 10 mars 2015

Dear friends, this is the problem I am facing now:



I have to determine the value of j, of a geometric progression that goes like this:



payments: 4 4(1+j) 4(1+j)^2 ....... 4(1+j)^19

Time : 0 1 2 3 ........ 20



where the payment of 4 is made at time 1 and the payment of 4(1+j)^19 is made at time 20. I am given that the periodic interest rate i = 0.03, and I am also given that the present value at time t = 0 is equal to 50.42893222.



This is clearly the present value of geometric annuity immediate, so what I formulated the problem as follows:



50.42893222 = 4* [ 1 - ( (1+j)/(1+i) )^20 ] / i - j



50.42893222 = 4* [ 1 - (1+j)^20 / (1.03)^20 ]/0.03 - j



Obviously, finding j is not straightforward, so I was hoping you guys could show me a trick (maybe using the TI BAII Plus or any other way) to solve for the growth rate.



Thanks, in advance for any guidance and/or help,



Best regards,



Paul





How to solve for growth rate in geometric annuities
 

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